2[10-5(x-2)]=1(x+1)

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Solution for 2[10-5(x-2)]=1(x+1) equation:


Simplifying
2[10 + -5(x + -2)] = 1(x + 1)

Reorder the terms:
2[10 + -5(-2 + x)] = 1(x + 1)
2[10 + (-2 * -5 + x * -5)] = 1(x + 1)
2[10 + (10 + -5x)] = 1(x + 1)

Combine like terms: 10 + 10 = 20
2[20 + -5x] = 1(x + 1)
[20 * 2 + -5x * 2] = 1(x + 1)
[40 + -10x] = 1(x + 1)

Reorder the terms:
40 + -10x = 1(1 + x)
40 + -10x = (1 * 1 + x * 1)
40 + -10x = (1 + 1x)

Solving
40 + -10x = 1 + 1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
40 + -10x + -1x = 1 + 1x + -1x

Combine like terms: -10x + -1x = -11x
40 + -11x = 1 + 1x + -1x

Combine like terms: 1x + -1x = 0
40 + -11x = 1 + 0
40 + -11x = 1

Add '-40' to each side of the equation.
40 + -40 + -11x = 1 + -40

Combine like terms: 40 + -40 = 0
0 + -11x = 1 + -40
-11x = 1 + -40

Combine like terms: 1 + -40 = -39
-11x = -39

Divide each side by '-11'.
x = 3.545454545

Simplifying
x = 3.545454545

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